Version: 2.0
The DatePart function returns the designated part of the
date.
Interval Settings
| SETTING | DESCRIPTION |
| YYYY | Year |
| Q | Quarter |
| M | Month |
| Y | Day Of Year |
| D | Day |
| W | WeekDay |
| WW | Week Of Year |
| H | Hour |
| N | Minute |
| S | Second |
| CONSTANT | VALUE | DESCRIPTION |
| VBSunday | 1 | Sunday |
| VBMonday | 2 | Monday |
| VBTuesday | 3 | Tuesday |
| VBWednesday | 4 | Wednesday |
| VBThursday | 5 | Thursday |
| VBFriday | 6 | Friday |
| VBSaturday | 7 | Saturday |
| VBFirstJan1 | 1 | Week of January 1 |
| VBFirstFourDays | 2 | First week of the year thathas at least four days |
| VBFirstFullWeek | 3 | First full week of the year |
| VBUseSystem | 0 | Use the date format of the computer's regionsl settings |
| VBUseSystemDayOfWeek | 0 | Use the first full day of the week as defined by the system settings |
<% =Date %>
<% =DatePart("D", Date) %>3/16/99
16<% =DatePart("W", 1/1/2000) %>7The weekday is given as a number from the Date And Time CONSTANTS which are listed below. In the example, 7 equals Saturday.
<% =DatePart("W", "1/1/2000", 3) %>5<% =DatePart("W", "1/1/2000", VBTUESDAY)
%>5In this example, Tuesday is defined to be the first day of the week.
Therefore, Saturday becomes the 5th day of the week.
<% =DatePart("WW", "12/31/1999", 1, VBFIRSTFULLWeek) %>52This example returns how many full 7 day weeks there were in 1999.